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(physics)Equilibrium and stability

(physics)Equilibrium and stability

A square cardboard of mass 5 g is pinned at one corner.When it is released at the position shown , what is the moment about the pin produced by its weight?

Answer : 0.007N m


show me the steps in detail and in depth , with steps or calculations stated ,either with labels or arrows and the clear steps annotated explicitly. thxxxxx.
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[隱藏]
Let centre of gravity be G
the position pin as P
PG = 20sin45 = 10sqrt.2cm = 0.1xsqrt.2 m
Moment = Fxd = mg xd =  (5 x 10^-3) x 10 x  0.1xsqrt.2
= 7.07x10^-3 Nm = 0.007Nm

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