integration

x-axis is a tangent of circle
find the formula of the circle

kin1205

Let the centre of the circle be (4,y)

y^2 = (8)^2+(4-y)^2
y^2 = 64 + 16 - 8y + y^2
y = 10

centre : (4,10)
radius : 10 units

Equation of circle :
(x-4)^2+(y-10)^2=100
or
x^2-8x+y^2-20y+16=0

integration

引用:

原帖由 kin1205 於 2011-7-9 12:35 AM 發表
Let the centre of the circle be (4,y)

y^2 = (8)^2+(4-y)^2
y^2 = 64 + 16 - 8y + y^2
y = 10

centre : (4,10)
radius : 10 units

Equation of circle :
(x-4)^2+(y-10)^2=100
or
x^2-8x+y^2-20y+1 ...

個centre根本唔系(4,y)
只系我畫得似

xXJohnXx

It is (4,y). Recall your knowledge from properties of circles

integration

引用:

原帖由 xXJohnXx 於 2011-7-9 01:01 PM 發表
It is (4,y). Recall your knowledge from properties of circles

終於明啦
本暑假作業超黑心
個p(4,0)特登唔畫centre下面==