本區搜索:
Yahoo!字典
打印

[M2] INTEGRATION

INTEGRATION

呢題應該要點IN我淨係計左呢埋野
之後就諗唔到啦....
附件: 您所在的用戶組無法下載或查看附件
   

TOP

[隱藏]
Wait your final step is inaccurate

Remind that when x=a,u=;x=0,u=a

Therefore it should be
I =  - integrate (0 to a) f(a-u)/[f(a-u)+f(u)] du
  = integrate (a to 0) f(a-u)/[f(a-u)+f(u)] du
= integrate (a to 0) f(a-x)/[f(a-x)+f(x)] dx [dummy variable]

RECALL Definition
I =integrate (a to 0) f(x)/[f(x)+f(a-x)] dx
= integrate (a to 0) f(a-x)/[f(a-x)+f(x)] dx [proven]

Therefore
2I= integrate (a to 0) f(x)/[f(x)+f(a-x)] dx + integrate (a to 0) f(a-x)/[f(a-x)+f(x)] dx
   = integrate (a to 0) [f(x)+f(a-x)]/[f(x)+f(a-x)] dx
   = integrate (a to 0) dx = a
So I = a/2

[ 本帖最後由 alexcheung2009 於 2014-3-29 12:38 AM 編輯 ]

TOP

Find the sum of the first line and last line, then divide by 2.

[ 本帖最後由 桃子 於 2014-3-29 12:59 AM 編輯 ]

TOP

引用:
原帖由 alexcheung2009 於 2014-3-29 12:30 AM 發表
Wait your final step is inaccurate

Remind that when x=a,u=;x=0,u=a

Therefore it should be
I =  - integrate (0 to a) f(a-u)/[f(a-u)+f(u)] du
  = integrate (a to 0) f(a-u)/[f(a-u)+f(u)] du
=  ...
點解當個負搖冇左之後會掉轉既?

TOP

this is one of the rules of integration
See
http://en.wikipedia.org/wiki/Integral
Press Ctrl+F to search for ''
Reversing limits of integration. If a > b then define
''

TOP

回覆 5# alexcheung2009 的帖子

原來係咁
THANKS但我唔係好明點解A係大過0

[ 本帖最後由 93039 於 2014-3-29 01:02 AM 編輯 ]

TOP

引用:
原帖由 93039 於 2014-3-29 12:47 AM 發表
點解當個負搖冇左之後會掉轉既?
Let F(x) be the antiderivative.

The definite integral from a to b is F(b)-F(a).
The definite integral from b to a is F(a)-F(b).

Hence, the sign reverse.

TOP

引用:
原帖由 93039 於 2014-3-29 12:53 AM 發表
原來係咁
THANKS但我唔係好明點解A係大過0
The expression also holds for a<0 and a=0.
The case a=0 should be trivial.

TOP

引用:
原帖由 alexcheung2009 於 2014-3-29 12:30 AM 發表
Wait your final step is inaccurate

Remind that when x=a,u=;x=0,u=a

Therefore it should be
I =  - integrate (0 to a) f(a-u)/[f(a-u)+f(u)] du
  = integrate (a to 0) f(a-u)/[f(a-u)+f(u)] du
= integrate (a to 0) f(a-x)/[f(a-x)+f(x)] dx [dummy variable]
點解可以轉返做X既

TOP

x is a dummy variable.



TOP

回覆 10# 桃子 的帖子

但題目LET左u=a-x
點解唔係咁樣計既
同埋咩係DUMMY VARIABLE...

[ 本帖最後由 93039 於 2014-3-29 03:10 PM 編輯 ]

TOP

function 入面舊野就係dummy variable

e.g.

假設有f(x) = x^2

咁f(a) = a^2     f(z) = z^2
入面舊野無影響 --> 個VARIABLE唔係重點

TOP

回覆 12# MrBenwong 的帖子

o...
明白哂

TOP

重要聲明:小卒資訊論壇 是一個公開的學術交流及分享平台。 論壇內所有檔案及內容 都只可作學術交流之用,絕不能用商業用途。 所有會員均須對自己所發表的言論而引起的法律責任負責(包括上傳檔案或連結), 本壇並不擔保該等資料之準確性及可靠性,且概不會就因有關資料之任何不確或遺漏而引致之任何損失或 損害承擔任何責任(不論是否與侵權行為、訂立契約或其他方面有關 ) 。