本區搜索:
Yahoo!字典
打印

[Maths] MC questions , please help me!!!!!

[隱藏]

MC questions , please help me!!!!!

for 23, ans: D
but i only found 2 pairs...
also, are there any skills to tackle this type of questions??

--------
for 24, ans:A
i don't know how to solve it...
also,are angle ABD=angle FDB , angle FBD=angle FDG (angle in alt. segment) ???

-----------
for 33 , ans:A
can x and y be -ve??

-------------
for 44, ans:C
i don't know how to solve it...

---------
for 46, ans:C
let O be the centre , OB=OD=r
10^2+ r^2 = (r+6)^2
r=16/3
so, BC=2r= 32/3
but why i am wrong....
can anyone show me the correct method??


thanks a lot!

[ 本帖最後由 LKY@123 於 2010-4-2 06:11 PM 編輯 ]
附件: 您所在的用戶組無法下載或查看附件
   

TOP

23


24


33
你試代x=-4 y=-5

44


46
我都5g

[ 本帖最後由 wongjaco 於 2010-4-2 06:37 PM 編輯 ]
理科@末代ce戰士任務終結,開始末代AL生崖
宗旨: 幫到人幫到自己 ; 有錯勿打 xdd
Heaven has no favourites

TOP

回覆 #2 wongjaco 的帖子

23, 即係點?
33, 我試過代-VE 的number , X,Y are non-zero integers 我問代 X,Y -VE 得唔得姐
24,are angle ABD=angle FDB , angle FBD=angle FDG (angle in alt. segment) ???

thanks for helping me!!

TOP

anyone can explain to me??

TOP

24 ABD=ADB (base ∠isos△)
     angle FBD=angle FDG (angle in alt. segment) ???是

23

理科@末代ce戰士任務終結,開始末代AL生崖
宗旨: 幫到人幫到自己 ; 有錯勿打 xdd
Heaven has no favourites

TOP

樓主.. 你係想要proof,,有d長, 大家能有快d  ge方法請告知小弟
let intersection of ac and bd = e
ac=bd
triangle abe ~ triangle cde
BE/ED=AE/EC   ------(1)
AC =BD            ------(2)

EC=ED
後面個D就好簡單,

個3個CONGRUENT TRI  :
TRIANGLE  ABD~=BAC           ADC~=BCD          AED~=BEC

最尾個題個答案應該係32/3, 唔係16/3

TOP

回覆 #6 manng825 的帖子

樓主.. 你係想要proof,,有d長, 大家能有快d  ge方法請告知小弟
let intersection of ac and bd = e
ac=bd
triangle abe ~ triangle cde
BE/ED=AE/EC   ------(1)
AC =BD            ------(2)

EC=ED
後面個D就好簡單,               which questions does it refer to ???



最尾個題個答案應該係32/3, 唔係16/3             會唔會BC=/= diameter ....?

TOP

回覆 #2 wongjaco 的帖子

for 33,, 我試過代-VE 的number , X,Y are non-zero integers 我問代 X,Y -VE 得唔得姐
for 44, how can you get 75degrees??

TOP

you shouldn't assume BC to be the diameter
BUT using another method, still cal. 32/3

附件: 您所在的用戶組無法下載或查看附件
Failing to prepare is preparing to fail!!!
想入好既大學,先要公開試考得好,更要jupas排得好!!!

想搵人補習??? Click on this:
http://www.lsforum.net/board/vie ... e%3D1&frombbs=1

TOP

回覆 #8 LKY@123 的帖子

you can sub x,y to be any non-negative integer with y<x
Failing to prepare is preparing to fail!!!
想入好既大學,先要公開試考得好,更要jupas排得好!!!

想搵人補習??? Click on this:
http://www.lsforum.net/board/vie ... e%3D1&frombbs=1

TOP

重要聲明:小卒資訊論壇 是一個公開的學術交流及分享平台。 論壇內所有檔案及內容 都只可作學術交流之用,絕不能用商業用途。 所有會員均須對自己所發表的言論而引起的法律責任負責(包括上傳檔案或連結), 本壇並不擔保該等資料之準確性及可靠性,且概不會就因有關資料之任何不確或遺漏而引致之任何損失或 損害承擔任何責任(不論是否與侵權行為、訂立契約或其他方面有關 ) 。