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[AMaths] 02 Q15

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02 Q15

for b)ii) ans, 點解有 "-" ??
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唔明樓主唔明d咩
【DSE Maths】中大教育文憑 × 數學系畢業◆助你奪*升Lv~
首次以課題分班,10月開班招生,快d黎睇下~

導師簡介:按此進入

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究竟請問唔明d咩???

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It depends on which side the point is located with respect to the straight line.
You can go back to the proof of the formula in your textbook. There are 2 cases.

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冇記錯可以用maths既linear ineuqality黎解.....
有錯請指正

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This is a concept that usually overlooked by students.
When the equation is represented in normal form,
i.e. xcosθ+ysinθ-p=0
p is always >=0
thus a negative sign is needed.
Look at your textbook for more reference

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ANS右下角EQUATION OF QS,
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呢題要解4條聯立方程
用計數機1分鐘ko

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引用:
原帖由 LKY@123 於 2010-5-3 11:51 AM 發表
ANS右下角EQUATION OF QS,
Split the absolute value sign, then you get 2 cases, +ve and -ve.

Solving them will give you two points on the different sides of the st. line.
For QS, the +ve case is rejected and you take the -ve case.

For RS, you also take the -ve case.
For QR, you take the +ve case.

[ 本帖最後由 桃子 於 2010-5-3 11:55 AM 編輯 ]

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