ctm_0011

幫手諗下點做...about log~~~thx

[ 本帖最後由 ctm_0011 於 2011-7-10 09:21 PM 編輯 ]

桃子

Let a=log p, b=log q, c=log r

x+y+z+2
=(b+c)/a + (a+c)/b + (a+b)/c + 2
=[bc(b+c) + ac(a+c) + ab(a+b) +  2abc] / abc

xyz
=(b+c)/a * (a+c)/b * (a+b)/c
=[(b+c)(a+c)(a+b)] / abc

If you expand [bc(b+c) + ac(a+c) + ab(a+b) +  2abc] and [(b+c)(a+c)(a+b)], they should be the same.

ctm_0011

thx~~~