thomas3253

引用:

原帖由 dororo988 於 2011-8-6 07:12 PM 發表
求x導數
1)y=3-2√(x)
2)y=4√(x)-1

1)
y=3-2x^0.5
y'=(3-2x^0.5)'
y'=(3)'-(2x^0.5)'
y'=0-2(x^0.5)'
y=-2(0.5)[x^(0.5-1)]
y'=-1(x^-0.5)

2)
y=4x^0.5-1
y'=(4x^0.5-1)'
y'=(4x^0.5)'-(1)'
y'=4(x^0.5)'-0
y'=4(0.5)[x^(0.5-1)]
y'=2x^-0.5