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[M1] M1數求教 (又一條probability)

M1數求教 (又一條probability)

又有條數唔識做, 求高手打救, 謝謝

Louis, a store owner who buys the iron rods from the factory, selects a box of iron rods randomly and checks each iron rod in the box one by one. If more than 3 unacceptable iron rods are found in a box, the whole box of iron rods will be returned to the factory.
One box contains 10 iron rods. The probability that an iron rod is acceptable is 0.92701512.

Given that the box of iron rods will be returned to the factory, find the probability that there are less than 5 unacceptable iron rods in the box.

Ans:0.9083
   

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[隱藏]
Let k = 0.92701512

P = (10C4)(k^6)(1-k)^4 / [1-k^10-(10C1)(k^9)(1-k)-(10C2)(k^8)(1-k)^2-(10C3)(k^7)(1-k)^3]
代友人徵數學科補習

提供:
小學數學 / 初中數學
高中Core / M1 / M2
補習

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計到了, 謝謝

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