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# [問題] 2008 AL Physics MC -Electrostatics

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## 我諗到啦，系咪咁呀?

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The left one is a -ve charged conductor.
The right one is an earthed conductor which becomes +ve
because of charging by induction.

The question asks about the change of the potential of the left conductor.

Recall:
(1) As the Electric Field inside a conductor is 0,
Potential is constant throughout the whole conductor.

(2) Electric potential of a point can be calculated by summing up k*dq/r

That is how to use the 2 points above:
Consider the potential of point A which is on the left bracket of the left conductor.
Because of the +ve charge on the right conductor,
V= k (+Q)/r_1 +  k (-Q)/r_2
obviously greater than the original potential.

Conclusion: More positive

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 christinali 學院師父 發短消息 加為好友 當前離線 3# 大 中 小 發表於 2012-11-14 04:04 PM (第 2163 天) 只看該作者 是不是Q13? (1) true. obviously the sphere becomes +ve charged. (2) false. 無啦啦charged conductor 點會lose +ve charge (3) false. 這不用多想吧....有個+ve charge brought near 個conductor, 明顯potential 唔會變得more -ve la.. UID279069 帖子713 精華0 積分143 閱讀權限40 在線時間484 小時 註冊時間2012-9-7 最後登錄2017-3-19  查看詳細資料 TOP
##### 引用:

(1) true. obviously the sphere becomes +ve charged.
(2) false. 無啦啦charged conductor 點會lose +ve charge
(3) false. 這不用多想吧....有個+ve charge brought near 個conductor, 明顯potent ...

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