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[問題] 有條yr 1數唔識做

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有條yr 1數唔識做

呢條唔識計, 麻煩唔該計埋
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I think this question is simply a drill of the product rule, quotient rule and chain rule in calculus of a single variable. Maybe what you should bear in mind are the following formulas:

(cos x)' = -sin x
(e^x)' = e^x
(arctan x)' = 1/(1+x²)
(sinh x)' = cosh x
(log x)' = 1/x

For example, (ii) can be done as follows:

(arctan(sinh x))' = (1/(1+sinh²x)) (sinh x)' = (1/(1+sinh²x)) (cosh x) = cosh x / cosh² x = 1/ cosh x ( cosh²x −sinh²x = 1).

The other two should be simple I think.

[ 本帖最後由 markckw76 於 2012-11-24 03:15 PM 編輯 ]

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thanks, i figured out how it works at the end

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就咁d 咋wor

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