93039

點解呢題既答案係 -INFINITY

smartboypm

當x由負數方向接近3
分子: (2x+1)^3->正數 (x-5)^4->正數
分母: (x-3)^3->負數 SQRT(9-x)->正數
所以最後得出既會係負數

93039

引用:

原帖由 smartboypm 於 2014-3-21 11:43 PM 發表
當x由負數方向接近3
分子: (2x+1)^3->正數 (x-5)^4->正數
分母: (x-3)^3->負數 SQRT(9-x)->正數
所以最後得出既會係負數

點解唔係等於0既加多一題
點解答案係-9?

桃子

Limit must be a finite number.
inf / -inf should not be given as the answer to a limit.

This limit is in the form k/0. Hence, the limit does not exist.

93039

引用:

原帖由 桃子 於 2014-3-21 11:50 PM 發表
Limit must be a finite number.
inf / -inf should not be given as the answer to a limit.

This limit is in the form k/0. Hence, the limit does not exist.

又問多一題
呢題點計

桃子

引用:

原帖由 93039 於 2014-3-22 12:01 AM 發表
又問多一題
呢題點計

1

Just put an extremely large number to check.

Simon

e^(-x) = 1 / (e^x)
When x tends to infinity, e^x tends to infinity