引用:
原帖由 y_1013 於 2014-4-29 01:40 PM 發表
Part B q1
我記得好似個長度係24sec(theta)+192csc(theta)
如果個長方形係24*192
我個方法係3個similar triangles
192/x=y/24=(y+192)/(x+24)=tan(theta)
y=4608/x
Pyth thm, root((192+y)^2+(24+x)^2)=root((192+4608/x)^2+(24+x)^2)
=root(37440+1769472/x+21233664/x^2+48x+x^2)
Since x=192/tan(theta)
=root(37440+1769472/x+21233664/x^2+48x+x^2)
=root(37440+9216tan(theta)+576(tan(theta))^2+9216cot(theta)+36864(cot(theta))^2)
歡迎各位指點錯處, 不過錯在會令我好過d, 因為呢個搞到我part b冇做