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# [Phy] AL PHY 2001 Q10 part cii Gases

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## AL PHY 2001 Q10 part cii Gases

10. Two containers A and B with volumes 100 cm3and 500 cm3 respectively are connected by a tube of negligiblevolume as shown in Figure 10.1.  The tap T for controlling gas flowis closed initially.  Container A contains an ideal gas ata pressure of 12 ´ 105 Pa while there is a vacuumin container B.  The temperature of the twocontainers is maintained at 0°Cby two separate water baths with melting ice.

(a)    Calculate the number of moles of gas incontainer A.

Ans : 0.0529 mol

(c)  The water bath for container A is heated until the water boils. The tap T remains open.  Calculate

(i)    the equilibrium pressure of the gas in thetwo containers;

Ans : 2.09 x 10 ^5 Pa

(ii)   the net amount of gas, in moles, that passedthrough the connecting tube during the heating process.

我既做法:

pV = nRT
(2.09 X10 ^5)(100*10^(-6)) = n (8.31)(100+273)
n= 0.00684 mol

So, the net amount of gas , in moles , that passed through the tube :

0.0529 - 0.00684  = 0.04606 mol

但 marking 就

So, the net amount of gas , in moles , that passed through the tube :

(0.0529 / 6) - 0.00684  = 0.04606 mol

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 Pockhin 高級學徒 發短消息 加為好友 當前離線 2# 大 中 小 發表於 2016-7-23 05:02 PM (第 700 天) 只看該作者 Please note that before A is heated, the gas has reached a steady equilibrium -->gas is evenly distributed in A and B -->the number of moles of gas in A is only 0.0529/6 mol, instead of 0.0529 mol that is why 0.0529 is divided by 6 before eliminating 0.00684 I hope this may give a help. UID348024 帖子248 精華0 積分31 閱讀權限20 在線時間562 小時 註冊時間2014-6-12 最後登錄2018-5-31  查看詳細資料 TOP
##### 引用:

Please note that before A is heated, the gas has reached a steady equilibrium
-->gas is evenly distributed in A and B
-->the number of moles of gas in A is only 0.0529/6 mol, instead of 0.0529 mol
...
Thank you 先.

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##### 引用:

Thank you 先.

I forget to explain the origin of 6
Actually 0.0529/6 is the number of moles of gas in A

In part (a) and (b), the number of moles of gas in A is not yet calculated
As the gas in A and B are of the same temperature and pressure
number of moles of gas is directly proportional to the volume
as volume of A: volume of B is 1:5
-->number of moles of gas in A: B is also 1:5
That's why the number of moles of gas in A is 0.0529/(1+5) mol
6科5**

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##### 引用:

I forget to explain the origin of 6
Actually 0.0529/6 is the number of moles of gas in A

In part (a) and (b), the number of moles of gas in A is not yet calculated
As the gas in A and B are of  ...

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