10. Two containers A and B with volumes 100 cm3and 500 cm3 respectively are connected by a tube of negligiblevolume as shown in Figure 10.1. The tap T for controlling gas flowis closed initially. Container A contains an ideal gas ata pressure of 12 ´ 105 Pa while there is a vacuumin container B. The temperature of the twocontainers is maintained at 0°Cby two separate water baths with melting ice.
(a) Calculate the number of moles of gas incontainer A.
Ans : 0.0529 mol
(c) The water bath for container A is heated until the water boils. The tap T remains open. Calculate
(i) the equilibrium pressure of the gas in thetwo containers;
Ans : 2.09 x 10 ^5 Pa
(ii) the net amount of gas, in moles, that passedthrough the connecting tube during the heating process.
我既做法:
pV = nRT
(2.09 X10 ^5)(100*10^(-6)) = n (8.31)(100+273)
n= 0.00684 mol
So, the net amount of gas , in moles , that passed through the tube :
0.0529 - 0.00684 = 0.04606 mol
但 marking 就
So, the net amount of gas , in moles , that passed through the tube :
(0.0529 / 6) - 0.00684 = 0.04606 mol
點解要除6既????
唔該