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[Core] 求解1985 ce maths

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求解1985 ce maths

Q50
計到19.04....度 依然計唔到ansA
我係用AC=3tan44 tan<CAQ=1」AC
之後我計到CAQ係19.04...度
Q53 我用三角形比例來計
我係(2」3)^2 +(1.5」3)^2=25」36
y要再除以2 先係ansDQ18唔識做help  thanks a lot

https://docs.google.com/file/d/0By_fBXid_HcUVVFwdTR3MWNxSTQ/edit
   

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Q50: I, too, have got 19.04... maybe there is a typo in the question?
Q52: angle BEA = angle ACE (angles in alternate segment), angle CBE = 30 + angle BEA = 30 + angle ACE (ext. angle of triangle)
180 = 100 + 30 + 2 * angle ACE (angle sum of triangle) => angle ACE = 25
The answer seems to be C, not D...
Q18: If you draw a right-angled triangle, you should have measurements of two sides of the triangle. Use Pythagoras Theorem, you should be able to find that the hypotenuse is a^2 + b^2. You can then make use of simple trigonometric relations to work out cos (theta). The answer should be B.

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