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[M2] limite

limite

Please help to solve the following problem


Thank you very much
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You've probably overthought this. What is the limit as x tends to negative infinity of 5^x? Just plug that in and you'll get it!

This limit is not in an indeterminate form (e.g. 0/0, infinity/infinity, etc.), so nothing fancy here.

[ 本帖最後由 風之男 於 2021-6-6 12:16 PM 編輯 ]

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回覆 2# 風之男 的帖子

Thank you for your kind assistance.
However, even we simply plug the negative infinity into x, how can we find the answer 1/2 ?




Thank you for your help, again

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引用:
原帖由 luckjoe 於 2021-6-6 03:47 PM 發表
Thank you for your kind assistance.
However, even we simply plug the negative infinity into x, how can we find the answer 1/2 ?




Thank you for your help, again
5^(-infty) = 1/(5^infty) "=" 0. Hence...
(btw, a calculator trick, try plugging in a really negative number and guesstimate the limit)

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回覆 4# 風之男 的帖子

Thank you very much

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你係唔係串錯字?

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